C Program to Find Count of Common Characters in Two Strings

#include<stdio.h>
#include<conio.h>
#include<string.h>
void main() {
    char str[1000], ch;
    int count = 0, i;
    printf("Enter a string: ");
    fgets(str, sizeof(str), stdin);
    printf("Enter a character to find its frequency: ");
    scanf("%c", &ch);
    for (i = 0; str[i] != '
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main() {
char str[1000], ch;
int count = 0, i;
printf("Enter a string: ");
fgets(str, sizeof(str), stdin);
printf("Enter a character to find its frequency: ");
scanf("%c", &ch);
for (i = 0; str[i] != '\0'; ++i) {
if (ch == str[i])
++count;
}
printf("Frequency of %c = %d", ch, count);
getch();
}
'; ++i) {
        if (ch == str[i])
            ++count;
    }
    printf("Frequency of %c = %d", ch, count);
    getch();
}

Output: