C program for converting regular expression to NFA

#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<ctype.h>
int r[100];
static int pos = 0;
static int sc = 0;
void nfa(int st, int p, char*s)
{
 int i,sp,fs[15],fsc=0;
 sp=st:pos=p;sc=st;
while(*s!=NULL)
{
if(isalpha(*s))
{
 r[pos++]=sp;
 r[pos++]=*s;
 r[pos++]=++sc;}
if(*s=='.')
{ 
 sp=sc;
 r[pos++]=sc;
 r[pos++]=238;
 r[pos++]=++sc;
 sp=sc;
}
 if(*s=='|')
{
 sp=st;
 fs[fsc++]=sc;
}
 if(*s=='*')
{
 r[pos++]=sc;
 r[pos++]=238;
 r[pos++]=sp;
 r[pos++]=sp;
 r[pos++]=238;
 r[pos++]=sc;
}
 if(*s=='(')
{
  char ps[50];
  int i=0,flag=1;
  s++;
while(flag!=0)
{
  ps[i++]=*s;
  if(*s=='(')
  flag++;
 if(*s==')')
  flag--;
  s++;
}
 ps[--i]='\0';
 nfa(sc,pos,ps);
 s--;
}
 s++;
}
 sc++;
for(i=0;i<fsc;i++)
{
 r[pos++]=fs[i];
 r[pos++]=238;
 r[pos++]=sc;
}
 r[pos++]=sc-1;
 r[pos++]=238;
 r[pos++]=sc;
}
void main()
{
 int i;
 char *inp;
 clrscr();
 printf("enter the regular expression :");
 gets(inp);
 nfa(1,0,inp);
 printf("\nstate intput state\n");
for(i=0;i<pos;i=i+3)
 print("%d  --%c--> %d\n", r[i], r[i+1], r[i+2]);
 printf("\n");
getch();
}