Design a Simple Calculator using Switch Statement in C

Simple Calculator Program in C:

#include<stdio.h>
#include<conio.h>
void main()
{
   int a, b, opt;
   clrscr();
   printf("Enter the First Number: ");
   scanf("%d",&a);
   printf("Enter the Second Number: ");
   scanf("%d",&b);
   for(;;)
   {
     printf("\n 1. Addition \n 2. Subtraction 
     \n 3. Multiplication \n 4. Division \n 
     5. Modulation \n 6. Exit \n");
     printf("\n\nEnter the your option: ");
     scanf("%d",&opt);
    switch(opt)
    {
      case 1:
      printf("\nThe Addition is %d\n", a+b);
      break;
      case 2:
      printf("\nThe Subtraction is %d\n", a-b);
      break;
      case 3:
      printf("\nThe Multiplication is %d\n", a*b);
      break;  
      case 4: 
      if(b==0)
      {
        printf("OOps Devide by zero\n");
      }
      else
      {
        printf("\nThe Division is %d\n", a/b);
      }  
      break;
      case 5:
      printf("\nThe Modulation is %d\n", a%b);
      break;  
      case 6: 
      return 0;
      break; 
      default:
      printf("\n Enter Correct Option\n");
      break; 
    }
  }
getch();
}

Output-1:

Output-2:

Output-3:

Output-4:

Output-5: